Question

The work function of a photoelectric material is 3.3 EV with threshold frequency will be

Answer 1

Answer:

5.2×10^33

Explanation:

E=Wo

hnew=Wo

new=Wo÷h

new=3.3÷6.626×10^-34=5.2×10^33

Answer 2

Given ,

• Work function (Wo) = 3.3 ev

It can be written as

Wo = 3.3 × 1.6 × (10)^(-19) v

We know that ,

The minimum energy required to pull an electron from a metal is called work function of metal

$\large \boxed{ \sf{W_{o} = hv_{o} }}$

Where ,

h = Plancks constant

Vo = Threshold frequency

Thus ,

$\mapsto \sf 3.3 \times 1.6 \times {(10)}^{ - 19} = \frac{6.6 \times {(10)}^{ - 34} }{v_{o}} \\ \\ \mapsto \sf v_{o} = \frac{1.6 \times {(10)}^{ - 19} }{2} \\ \\ \mapsto \sf v_{o} = 0.8 \times {(10)}^{15} \: hertz$

$\sf \therefore\underline{ The \: threshold \: frequency \: is \: 0.8 \times {(10)}^{15} \: hertz }$