Question

The work function of a surface of a photosensitive material is 6.2 e.V. The wavelength of the incident radiation for which the stopping potential is 5 V lies in the :

Answer 1

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Answer 2

Answer:

Ultraviolet region

Explanation:

Work function of a surface of a photosensitive material = 6.2 eV (Given)

Wavelength of the incident radiation = 5 V (Given)

According to the laws of the photoelectric effect -  

Kemax = E − ϕ

where is the function and Kemax is the maximum kinetic energy of the photoelectron. Thus, -  

=  eV0 = E − ϕ

= E = eV0 + ϕ

= 5eV+6.2 eV

= 11.2 eV

=  λ =(12400/11.2)A

= 1000 A

Hence, the radiation lies in ultraviolet region.