Question

The work function of aluminium is 4.2 eV. If two photons , each of energy 3.5 eV strike an electron of aluminium , then emission of electrons will be

Answer 1

Answer:

The emission of electrons is not possible

Explanation:

We Know That

KE = hv - W

where, W= Work function

Here,

hv > W to have KE but given that

W=4.2, hv=3.5

i.e hv<W

Therefore, The emission of electron is not possible

Answer 2

Answer :-

In this case, the photoelectric emission does not occur.

Photoelectric effect deals with interaction of single photon with single electron. And, emission occurs only when energy of each individual incident photon is greater than than work function of than given metal.

But, in this case, energy of each striking electron is 3.5 eV which is less than the work function of Aluminum metal which is 4.2 eV. Hence, emission will not occur.

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