Physics, asked by sumitpawar1160, 1 year ago

The work function of caesium is 2.14eV.find a)threshold frequency.b) the wavelength of incident light if the photocurrent is brought to zero by a stopping potential of 0.60v

Answers

Answered by DhananjayJha
5
joules



In physics, the electronvolt (symbol eV, also written electron-volt and electron volt) is a unit of energy equal to approximately 1.6×10−19 joules(symbol J). By definition, it is the amount of energy gained (or lost) by the charge of a single electron moving across an electric potential difference of one volt.

Answered by dasbikram095
3

a) v=5.2*10^14hz

b)wavelength=4.5*10^-7m

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