Physics, asked by agemub, 7 months ago

the work function of caesium metal is 2.14ev​

Answers

Answered by anshikagoswami16
7

Answer:

hope it will help you

Explanation:

When light of frequency 6 ×1014 Hz is incident on the metal surface, photoemission of electrons occurs. Hence, the maximum kinetic energy of the emitted electrons is 0.345 eV. ...

thank you

please follow me and Mark me as a brainliest

Answered by prasuna2147
4

ANSWER:

Work function, ϕ o=2.14eV

Work function, ϕ o=2.14eVFrequency of light, ν=6×10 14 Hz

HzMaximum K.E. is given by the photoelectric effect.

HzMaximum K.E. is given by the photoelectric effect.K=hν−ϕ

K=(6.626×10^ −34×6×10^ 14)/1.6×10^-19) −2.14

=0.345eV

mark as brainliest

Similar questions