the work function of metals A B and C are respectively 1.92 eV,2.0eV,5.0ev. according to Einstein equation the metal which will EMIT photoelectrons for radiation of wavelength 4100A is........
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Metal A and B will emit photo-electrons.
Explanation:
Energy of radiation = hv
= hc/ λ
= 1240/410
= 3.02 eV
- Since energy of incident radiation is greater than the work function of metals A and B
- Thus metal A and B will emit photo-electrons.
- Since work function of /c is more than 3 eV, therefore it will not emit.
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Calculate the wavelength of photon having energy 5 e.v. ?
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