Question

The work of 146 KJ is performed in order to compress one kilo mole of a gas adiabatically and in this process , the temprature of the gas increase by 7°C . the gas is (R = 8.3Jmol⁻¹ K⁻¹ ) [AIEEE 2006] ​

Answer 1

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Answer 2

Explanation:- For adiabatic process ,no exchange of heat .

∴ dQ = 0

So, dU = -ΔW

⟹ nCᵥdt = +146× 10³J

⟹ nfR/2 × 7 = 146 × 10³ [Where, f is degree of freedom] ∴ Cᵥ = fR

⟹ 10³ × f × 8.3× 7 /2 = 146× 10³

⟹f = 5.02≈ 5

∴ it is a diatomic gas .