Math, asked by Kamalchaudhary204, 2 months ago

The work of a student to solve a set of equations is shown: Equation 1: m = 8 + 2n Equation 2: 4m = 4 + 4n Step 1: −4(m) = −4(8 + 2n) [Equation 1 is multiplied by −4.] 4m = 4 + 4n [Equation 2] Step 2: −4m = −32 − 8n [Equation 1 in Step 1 is simplified.] 4m = 4 + 4n [Equation 2] Step 3: −4m + 4m = −32 − 8n + 4n [Equations in Step 2 are added.] Step 4: 0 = −32 − 4n Step 5: n = −8 In which step did the student first make an error? Step 1 Step 2 Step 3 Step 4

Answers

Answered by sumitsharma10012005
0

student di error in step 2

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