Question

the work sone is carrying a charge of 2 micro coulomb point A to B is 6 ×10 power _4 joule the potential difference between these point will be

Answer 1

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Answer...

$potential \: between \: two \: points \: = \frac{work \: done}{charge} \\ \\ v \: = \frac{6 \times {10}^{ - 4} }{2 \times {10}^{ - 6} } \\ \\ v \: = 3 \times {10}^{2} \: v$

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Answer 2

w=qV

where, w=6×10^4 J

and q=2×10^-3 C

V =w/q

V= (6×10^4)/(2×10^-3

V=3×10^7 volt ANS.

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