Question

the work was carried out on the gas 55j with its internal energy increased by 15j the heat the gas got in proceses what is the amount of heat???​

Answer 1

Solution:- (C) −10J

As the heat is given to the system and work is done by the system, therefore,

q=+10J

W=−20J

Now from the first law of thermodynamics,

ΔU=q+W

⇒ΔU=10+(−20)=−10J

Hence the change in internal enrgy is −10.

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