Physics, asked by sharmaayan9830, 1 month ago

The working formula of coefficient viscosity of water determined by the method of
capillary flow is as follows (symbols have their conventional meaning)
πρgr4h
81V
For determination of the coefficient of viscosity by this experimental method V
versus h graphis plotted. The graph should be
n =​

Answers

Answered by shaswatsingh34
0

Answer:Poiseuille investigated the steady flow of a liquid through a capillary tube. He derived an expression for the volume of the liquid flowing per second through the tube.

Consider a liquid of co-efficient of viscosity η flowing, steadily through a horizontal capillary tube of length l and radius r. If P is the pressure difference across the ends of the tube, then the volume V of the liquid flowing per second through the tube depends on η, r and the pressure gradient p/l.

(i.e) V α ηx r y (P /l)z

V=k ηx r y (P /l)z

where k is a constant of proportionality. Rewriting equation (1) in terms of dimensions,

[L3T-1] = [ML-1 T-1] x [L]y[ML-1T-2 / L]z

Equating the powers of L, M and T on both sides we get x = -1, y = 4 and z = 1

Substituting in equation (1),

V= kPr4/ ηl

Experimentally k was found to be equal to π/ 8

V = πPr4 / 8 ηl

 

This is known as Poiseuille's equation.

Explanation:

Answered by singh121sandy010
0

Answer:

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