Question

The world record for the pole vault is 6.15 m. If the pole vaulter’s gravitational potential energy is 4942 J, what is his mass?
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Answer 1

Answer:

m=82kg

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Answer 2

Answer:

Gravitational potential energy is given by

Gravitational potential energy is given by U

Gravitational potential energy is given by U=

Gravitational potential energy is given by U=m

Gravitational potential energy is given by U=mg

Gravitational potential energy is given by U=mgh

Gravitational potential energy is given by U=mgh , where

Gravitational potential energy is given by U=mgh , where m

Gravitational potential energy is given by U=mgh , where m is the mass of the object,

Gravitational potential energy is given by U=mgh , where m is the mass of the object, h

Gravitational potential energy is given by U=mgh , where m is the mass of the object, h is the height of the object above the ground (Earth's surface), and

Gravitational potential energy is given by U=mgh , where m is the mass of the object, h is the height of the object above the ground (Earth's surface), and g

Gravitational potential energy is given by U=mgh , where m is the mass of the object, h is the height of the object above the ground (Earth's surface), and g is the gravitational acceleration constant,

Gravitational potential energy is given by U=mgh , where m is the mass of the object, h is the height of the object above the ground (Earth's surface), and g is the gravitational acceleration constant, 9.8

ms2.

For h

=

=6.15

m and u

=

=4942J

, we can rearrange to solve for

m:

m

m=

Ugh

m

m=

m=4942J

9.8

ms2.

6.15m

m

m≈

m≈82kg

Explanation:

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