Question

The wt. of an object is 25N in air.The wt. of the object is 18N in water. Then, 1).What is the upthrust given by water? 2).What is the wt. of displaced water?

Answer 1

Answer:

THE ANSWER IS:

•ANS 1). 7 NEWTONS.

•ANS 2). 700 GRAM FORCE OR 700 gf.

Explanation:

•WE SOLVE LIKE THIS:

•ANS 1). WEIGHT OF THE OBJECT IN AIR - 25 NEWTONS.

WEIGHT OF THE OBJECT IN WATER - 18 NEWTONS

THEREFORE,

UPTHRUST GIVEN BY THE WATER

= WEIGHT OF OBJECT IN AIR - WEIGHT OF OBJECT IN WATER

= 25 NEWTONS - 18 NEWTONS

= 7 NEWTONS.

•ANS 2). 1 NEWTON = 100 GRAM FORCE OR 100 gf

7 NEWTONS = 7 x 100

= 700 GRAM FORCE OR 700 gf.

HOPE IT HELPS YOU.

Answer 2

Explanation:

Weight in air = 25N

Weight in water = 18N

Upthrust given by water = 25 - 18 = 7N

Archimedes' principle states that Buoyant force is equal to the weight of the water displaced

So, weight of displaced water = 7N