Question

The wt. of NO having the same no. of oxygen atom present in 9.2 gm of NO2.
(A) 9.2 gm
(B) 6 gm
(C) 12 gm
(D) 24 gm

With explanation and will be marked as brainliest.​

Answer 1

Answer:

Explanation:

9.2/46×2= w/30

W= 12gm Ans

Answer 2

Answer:

ans ~ 12g

Explanation:

no. of moles of N = 9.2/14 =0.2 moles

1 mol of NO2 have 2 oxygen atom

so,

0.2 mol have 0.4 oxygen atom

now in NO

1Mol have 1 oxygen atom

no. of O atom in NO2 = no. of O atom in NO

so how many moles will have 0.4 atom

SO 0.4 mol have 0.4 O atom

weight of 0.4 mol of NO = 0.4 ×30

=12g