Question

the x component of a certain vector is 2 units and y component is 2√3 units . what is the magnitude of the vector​

Answer 1

the magnitude of the vector is

square root of(4+12)=4

Answer 2

Answer:

The magnitude of the given vector​ is 4 units.

Step-by-step explanation:

Given the x-component of the vector, let $\vec V_x= 2\hat i$

And the y-component of the vector, $\vec V_y= 2\sqrt{3} \hat j$

• A vector has both magnitude and direction.
• The magnitude of a vector gives the numeric value associated with a vector quantity.
• Consider a vector, $\vec V=a\hat i+b\hat j+c\hat k$ with $a, b, c$ as the direction ratios along the x-, y- and z-axis.
• Then the magnitude of the vector is equal to the square root of the sum of the squares of its direction ratios,  $|\vec V|=\sqrt{a^{2} +b^{2} +c^{2} }$

Substituting the values to find the magnitude of the given vector,

$|\vec V|= \sqrt{V_x^2+V_y^2}$

     $= \sqrt{2^2+\big(2\sqrt{3}\big)^2} = \sqrt{4+4\times 3}$

     $=\sqrt{4+12} =\sqrt{16} =4$

Therefore, the magnitude of the given vector​ is 4 units.