Question

The x- coordinate of a point P is twice the y-coordinate. If P is equidistant from
Q(2,-5) and R(-3,6), find the coordinates of P.​

Answer 1

Answer:

Given:

x-coordinate of P =2y

Point P is equidistant from Q and R

Step-by-step explanation:

PQ=PR.....given ....1

Therefore,PQ²=PR².....from eq 1

(x-2)²+[y-(-5)]²=[x-(-3)²]+(y-6)²

x²+2²-2×2×x+y²+5²+2×5×y=x²+3²+2×3×x+y²+6²-2×6×y

4-4x+25+10y=9+6x+36-12y

4+25-36-9=4x+6x-12y-10y

-16=10x-22y

10x-22y+16=0

10×2y-22y+16=0

20y-22y+16=0

-2y+16=0

-2y=-16

y=16/2

y=8...2

But,

x=2y

x=2×8

x=16

(x,y)=(16,8) are the coordinates of point P