Question

The X-linked recessive trait of color-blindness is present in 5% of males. If a mother who is a carrier and father who is unaffected plan to have 2 children, what is the probability the children will both be male and color-blind?​

Answer 1

Explanation:

• Carrier Mother wil have = Xc X
• Unaffected Father will have = X Y

From crossing

Parent — Mother × Father

Xc X X Y

Gametes — Xc , X X , Y

Offspring Xc X , X X , Xc Y , X Y

Conclusion :

—Two girl - one is Carrier Xc X , other in unaffected XX.

—Two boys - one is colourblind Xc Y , other in unaffected XY.

• 25 % chances are there that the children is male & colourblind