Question

The y component of vector |A|=15 units when it forms an angle of 50°with positive X axis
a)9.6 units
b)-9.6 units
c)11.5 units
d)-11.5 units
​

Answer 1

Explanation:

15 sin 50⁰ = 15 x 0.76 = 11.5 units

Answer 2

Answer:

Y component o vector =$15*sin(50^o) = 11.5$

Explanation:

Magnitude of vector A = 15 units.

Breaking the components of the vector A along x and Y axis.

As shown in the diagram,

Y-component of the vector is $Asin(50^o)$

and X-component of the vector is $Acos(50^o)$

Y component o vector = $15*sin(50^o) = 11.49$

To verify this:

X component of vector A = $15*cos(50^o)=9.64$

magnitude of vector sum of X and Y component must be equal to magnitude of original vector itself.

$\mid \vec A \mid = \sqrt{(15.cos(50^o))^2+(15.sin(50^o))^2} = \sqrt{(15^2(sin(50^o)^2+cos(50^o)^2)}=\sqrt{15^2} = 15$

#SPJ3