Question

The y-intercept of the equation of the line
3x + 12y + 8 = 0 is​

Answer 1

Given :

• 3x +12y+8 = 0

To find :

• y-intercept of the given equation of the line.

Solution :

To find y-intercept of the equation of the line put x = 0 in the equation.

So we will put x = 0 in 3x +12y+8 = 0.

$\implies \sf3x + 12y + 8 = 0$

$\implies \sf(3 \times 0) + 12y + 8 = 0$

$\implies \sf0 + 12y + 8 = 0$

$\implies \sf 12y= - 8$

$\implies \sf y= \dfrac{ - 8}{12}$

$\implies \sf y= \dfrac{ \cancel{ - 8} \: \: \: - 2}{ \cancel{12} \: \: \: 3}$

$\implies \sf y= \dfrac{ - 2}{ 3}$

Answer :

The y-intercept of the equation of the line

3x + 12y + 8 = 0 is = -2/3

___________________

Additional Information :-

If we have to find out x-intercept then we will put y = 0 in the equation of line and the then we will get x intercept.