The yellow flame shown by sodium in bunsen flame is due to excitation of electrons
a)2p to 3s
b)3p to 1s
c)4p to 4s
d)5p to 4s
correct option is a
please explain with reason
Answers
Answered by
8
the answer will be 'a'
the electronic configuration of sodium atom =
1s2 2s2 2p6 3s1 when not in excited state.
the 3S orbital is not completely filled so when sodium is burned in Bunsen burmer due to the excited state the electron from 2P orbital jumps to 3S orbital to fill it
the electronic configuration of sodium atom =
1s2 2s2 2p6 3s1 when not in excited state.
the 3S orbital is not completely filled so when sodium is burned in Bunsen burmer due to the excited state the electron from 2P orbital jumps to 3S orbital to fill it
Answered by
1
Explanation:
The correct option Is a
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