Question

The YMCA lap pool is a right rectangular prism 36.8m long by 20m wide. The pool contains 1472m cubed of water.
How deep is the water in the pool?

Answer 1

Answer:

2m

Step-by-step explanation:

volume of the pool = b*h*d

d=volume/(b*h)

d=1472/(36.8*20)

d=2m

Answer 2

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\tt{\therefore{Height\:of\:pool=2\:m}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{\underline \bold{Given: }} \\ \tt: \implies length \: of \: pool = 36.8 \:m \\ \\ \tt: \implies Breadth \: of \: pool = 20\: m \\ \\ \tt: \implies Volume \: of \: pool= 1472\:m^{3}\\\\\red{\underline \bold{To \: Find: }} \\ \tt: \implies Height \: of \: pool = ?$

• According to given question :

$\bold{As \: we \: know \: that} \\ \tt: \implies Volume \: of \: pool= l \times b \times h \\ \\ \tt: \implies 1472 = 36.8 \times 20\times h \\ \\ \tt: \implies 1472 = 736 \times h \\ \\ {\tt: \implies h = \frac{1472}{736}}$

$\green{ \tt: \implies h = 2 \: m} \\ \\ \green{ \tt \therefore Height \: of \: pool \: is \: 2 \: m} \\ \\ \purple{ \bold{Some \: related \: formula \: to \: this \: topic}} \\ \pink{\tt\circ \: L.S.A \: of \: cuboid = 2(l + b)h} \\ \\ \pink{\tt\circ \: T.S.A\: of \: cuboid = 2(lb + bh + hl)}$