Physics, asked by jahanvi3851, 8 months ago

The Young's modulus of a material having a cross-sectional area of 1cm^2 is 2×10^12 dyne/cm^2. If the length is to be doubled the force required is

Answers

Answered by sanatkumarnaik499

0

Answer:

2×10^12dyne

Explanation:

you know the formula Y=FL/A∆L. ∆L=2L-L=L. by substituting F=2×10^12dyne

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