Question

The Young's modulus of a material
having a cross-sectional area of 1cm2 is
2x10¹² dyne/cm². If the length is to be
doubled the force required is
1) 4 x 10⁷ N
2) 2 x 10⁷ N
3) 10⁷ N
4) Zero​

Answer 1

Answer:

Given : Y = 2 * 10 ^12 Dyne/cm^2

Acc to formula Y = F * L / A * dL

Y modulus directly proportional to Length .If length is twice , Area will be doubled then ,then net change is Zero ,no change in Young modulus so Young modulus remain unchanged.

#option 2 is the correct answer