Physics, asked by katherine1212, 9 months ago

The Young's modulus of a rope of 10 m length and
having diameter of 2 cm is 20.0 x 10" dyne/cm². If
the elongation produced in the rope is 1 cm, the force
applied on the rope is
(a) 6.28 x 10 N
(b) 6.28 x 104 N
(c) 6.28 x 10* dyne (d) 6.28 x 10° dyne​

Answers

Answered by arsheeno19
0

option B is your answer

Attachments:
Similar questions