Question

The young's modulus of the material of a wire is 2 x 1010 nm^2. If the elongation strain is 1 %, then the energy stored in the wire per unit volume in k m ^3 is

Answer 1

Energy stored in wire per unit volume= 1/2 × Stress × strain

=1/2 × Y × (Strain)²

= 1/2 × 2 × 1010 × (0.01)²

= 1010 × 0.0001

= 0.1010 Nm²

Answer 2

Answer:10^6

Explanation:0.5 * stress* strain

0.5*Y*strain^2

=0.5*2*10^10*((10^-2)^2)

=

10^6