Question

The younger brother was 3/4th the age of the older brother in 2003. 12 years later, the younger brother was 5/6th the age of the older brother. what year was the younger born?

Answer 1

Hey friend,
He was born in 1994.

Answer 2

Answer:

1985

Step-by-step explanation:

Let the age of older brother in 2003 be x

The younger brother was 3/4th the age of the older brother in 2003.

Younger brother's age in 2003 = $\frac{3}{4}x$

Older brother's age after 12 year = x+12

Younger brother's age after 12 year= $\frac{3}{4}x+12$

Now we are given that 12 years later, the younger brother was 5/6th the age of the older brother.

So, $\frac{3}{4}x+12=\frac{5}{6}(x+12)$

$x=24$

the age of older brother in 2003 is 24

Younger brother's age in 2003 = $\frac{3}{4}(24)=18$

So, the younger born was born in year = 2003-18=1985

Hence the younger born was born in 1985.