The youngs modulus of brass and steel are respectively 1.0 10 11 n m 2 and 2.0 10 11 n m 2 1.01011nm2and2.01011nm2. A brass wire and steel wire of the same length are extended by 1 mm mm each under the same force. If radii of brass and steel wires are r b and r s rbandrs respectively, then
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Answer:
Increase in length,
ΔL=FLY.A=FLY.πR2
Δ
L
=
F
L
Y
.
A
=
F
L
Y
.
π
R
2
As F, L and ΔL
Δ
L
are same hence, Y.R2=aconstant
Y
.
R
2
=
a
c
o
n
s
tan
t
∴
∴
2.0×1011R2s=1.0×1011R2B
2.0
×
10
11
R
s
2
=
1.0
×
10
11
R
B
2
⇒
⇒
Rs=RB2√
Explanation:
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