Question

the zereos of quadratic polynomial x2 + 13x +40 are?​

Answer 1

Step-by-step explanation:

1.1 Factoring x2-13x+40

The first term is, x2 its coefficient is 1 .

The middle term is, -13x its coefficient is -13 .

The last term, "the constant", is +40

Step-1 : Multiply the coefficient of the first term by the constant 1 • 40 = 40

Step-2 : Find two factors of 40 whose sum equals the coefficient of the middle term, which is -13 .

-40 + -1 = -41

-20 + -2 = -22

-10 + -4 = -14

-8 + -5 = -13 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -8 and -5

x2 - 8x - 5x - 40

Step-4 : Add up the first 2 terms, pulling out like factors :

x • (x-8)

Add up the last 2 terms, pulling out common factors :

5 • (x-8)

Step-5 : Add up the four terms of step 4 :

(x-5) • (x-8)

Which is the desired factorization

Equation at the end of step

1

:

(x - 5) • (x - 8) = 0

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Answer 2

Step-by-step explanation:

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