Question

The zero error of the Vernier calipers shown in Figure 10 is 0.9 mm. What is the

diameter of the sphere being measured in the Figure​

Answer 1

Answer:

31.5mm

reading is 3.24 CM = 32.4mm

erro is 0.9 ( means if Diameter were zero the reading would be 0.9mm)

Dia = reading - ZE = 32.4-0.9= 31.5

Answer 2

Concept

A vernier calliper is defined as a measuring device that is used for the measurement of linear dimensions. It is also used for the measurement of diameters of round objects with the help of the measuring jaws.

Given

A figure is given in which the zero error of vernier calipers is $0.9mm$.

Find

We have to find the diameter of the sphere being measured in the given figure.

Solution

The Least count from the given figure is

$LC=1MSD-1VD$

Here, main scale division is $1mm$ and vernier scale division is $\frac{9}{10}mm$.

Therefore, $LC=1mm-0.9mm=0.1mm$

Now, we will find the diameter of the sphere is

$D=MSR+VSD\times LC$

$\Rightarrow D= 1mm+0.9\times0.1$

$\Rightarrow D=1.09mm$

Hence the diameter of the sphere is $1.09mm.$

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