Question

The zero of P(x ) = x²-1​

Answer 1

Answer:

${x}^{2} - 1 = 0 \\ {x}^{2} - {1}^{2} = 0 \\ (x - 1)(x + 1) = 0 \\ x = 1 \: \: \: or \: \: \: x = - 1$

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Answer 2

Step-by-step explanation:

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let x²-1 =0

=> x²=1

=> x=+-1

thus, the zeroes of the polynomial are:

• +1
• -1

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