Question

the zero of polynomial of x square - 9​

Answer 1

Answer:

Step-by-step explanation:

If one of the zero is reciprocal of the other, let one zero be α other zero will be 1/α

Product of roots = c/a = α × 1/α = 6a/(a²+9) = 1 = 6a/(a²+9) = a² + 9 = 6a = a² – 6a + 9 = 0 = a² – 3a – 3a + 9= 0 = a(a-3) -3(a-3) = 0 = (a-3)(a-3) = 0 = (a-3)²= 0 a = 3

Value of a is 3.

Answer 2

3 & - 3

Step-by-step explanation:

Zero of polynomial x² - 9

=> x² - 9 = 0

=> x² - 3² = 0

=> (x + 3)(x - 3) = 0

[using formula a² - b² = (a+b)(a-b), here a = x & b = 3]

Case 1 -

x + 3 = 0

=> x = -3

Case 2 -

x - 3 = 0

=> x = 3

So,

zeroes are 3 & -3.

hope it helps.