Question

The zero of the following polynomial is..
P(x) =6x²-3

Answer 1

Root 1/2 is the answer

Answer 2

6x^2 - 3 = 0

=> 6x^2 = 3

=> x^2 = 3/6

=> x^2 = 1/2

${x}^{2} = \frac{1}{2} \\ \\ x = + - \sqrt{ \frac{1}{2} } \\ \\ zeroes \: are \: + \sqrt{ \frac{1}{2} } \: and \: - \sqrt{ \frac{1}{2} }$