Question

the zero of the polynomial 2x³+x2+x-3​

Answer 1

Answer:

2x³+x²-6x-3,

then two roots are

x=-√3,x=√3

(x+√3)(x-√3)=x²-y²

x²-(√3)²

x²-3 this will divide this eq. 2x³+x²-6x-3

x²-3)2x³+x²-6x-3(2x+1

2x. -6x

(-). (+)

_________

x²-3

x²-3

(-). (+)

_________

after it I think its two roots are 0,3

$\huge\mathfrak\red{∆SingleTomorrow}$