The zero of the polynomial 6x^3–4x–2 is;
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Answer:
Zero = 1 , or factor = ( x -1)
Step-by-step explanation:
Provided that polynomial
= 6x³ - 4x - 2
Now as we know that , the value of x for which the polynomial is equal to zero is it's zero ,
Also as it is a polynomial of degree 3 , so we have to find a zero by hit and trial method.
Now put x = 1 in the polynomial
= 6(1)³ - 4(1) - 2
= 6 - 4 - 2
= 0
so x = 1 is zero or (x -1) is a factor of this polynomial
Now we are gonna apply long division method in order to find other zeros
(6x³ - 4x - 2) ÷ (x - 1)
= 6x² + 6x + 2
Now as 6x² + 6x + 2 will give imaginary roots , hence only 1 is it's answer.
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