Question

the zero of the polynomial f(k)=8k+32 is a)-4b)4c)-24​

Answer 1

Answer:

let f(k)=0

8k+32=0

k= -4

therefore, option a

Answer 2

Answer:

a) -4

Step-by-step explanation:

f(k)=8k+32

f(-4) = 8×(-4) +32

= - 32 +32

=0