The zero of the polynomial p(x)=49x^2-7x is ____
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Answer:
0 and 1/7
Step-by-step explanation:
Given polynomial : 49x^2 -7x
Take 7x common
= 7x * (7x - 1)
Therefore for x = 0 , or x = 1/7, either part becomes 0 , and the total value is also 0
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