Math, asked by sibichakravarthiss, 5 hours ago

The zero of the polynomial p(x)=49x^2-7x is ____

Answers

Answered by itsRakesh

0

Answer:

0 and 1/7

Step-by-step explanation:

Given polynomial : 49x^2 -7x

Take 7x common

= 7x * (7x - 1)

Therefore for x = 0 , or x = 1/7, either part becomes 0 , and the total value is also 0

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