The zero of the polynomial p(x) = 4x - pi
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Answer:
hey buddy,
here is your answer..
Step-by-step explanation:
\begin{gathered}p(x) = (4x + \pi)(x - 4\pi) \\ zeroes \:are... \\ 4x + \pi = 0 \\ x = \frac{ - \pi}{4} = - \frac{22}{7} \times \frac{1}{4} = \frac{ - 11}{14 } \\ \\ x - 4\pi = 0 \\ x = 4\pi = 4 \times \frac{22}{7} = \frac{88}{7}\end{gathered}
p(x)=(4x+π)(x−4π)
zeroesare...
4x+π=0
x=
4
−π
=−
7
22
×
4
1
=
14
−11
x−4π=0
x=4π=4×
7
22
=
7
88
I hope this will help you
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