Math, asked by gitadharecha1234, 16 days ago

the zero of the polynomial p(x)=5x^3-2x^2+3x-2is_

Answers

Answered by trinadhsai888

Answer:

p(x)=2x

p(x)=2x 2

p(x)=2x 2 −5x−3

p(x)=2x 2 −5x−3To find zero of polynomial p(x)=0

p(x)=2x 2 −5x−3To find zero of polynomial p(x)=0p(x)=2x

p(x)=2x 2 −5x−3To find zero of polynomial p(x)=0p(x)=2x 2

p(x)=2x 2 −5x−3To find zero of polynomial p(x)=0p(x)=2x 2 −5x−3

p(x)=2x 2 −5x−3To find zero of polynomial p(x)=0p(x)=2x 2 −5x−3p(x)=0

p(x)=2x 2 −5x−3To find zero of polynomial p(x)=0p(x)=2x 2 −5x−3p(x)=0⇒2x

p(x)=2x 2 −5x−3To find zero of polynomial p(x)=0p(x)=2x 2 −5x−3p(x)=0⇒2x 2

p(x)=2x 2 −5x−3To find zero of polynomial p(x)=0p(x)=2x 2 −5x−3p(x)=0⇒2x 2 −5x−3=0

p(x)=2x 2 −5x−3To find zero of polynomial p(x)=0p(x)=2x 2 −5x−3p(x)=0⇒2x 2 −5x−3=0⇒2x

p(x)=2x 2 −5x−3To find zero of polynomial p(x)=0p(x)=2x 2 −5x−3p(x)=0⇒2x 2 −5x−3=0⇒2x 2

p(x)=2x 2 −5x−3To find zero of polynomial p(x)=0p(x)=2x 2 −5x−3p(x)=0⇒2x 2 −5x−3=0⇒2x 2 −6x+x−3=0

p(x)=2x 2 −5x−3To find zero of polynomial p(x)=0p(x)=2x 2 −5x−3p(x)=0⇒2x 2 −5x−3=0⇒2x 2 −6x+x−3=0⇒2x(x−3)+1(x−3)=0

p(x)=2x 2 −5x−3To find zero of polynomial p(x)=0p(x)=2x 2 −5x−3p(x)=0⇒2x 2 −5x−3=0⇒2x 2 −6x+x−3=0⇒2x(x−3)+1(x−3)=0⇒(2x+1)(x−3)=0

p(x)=2x 2 −5x−3To find zero of polynomial p(x)=0p(x)=2x 2 −5x−3p(x)=0⇒2x 2 −5x−3=0⇒2x 2 −6x+x−3=0⇒2x(x−3)+1(x−3)=0⇒(2x+1)(x−3)=0x=

p(x)=2x 2 −5x−3To find zero of polynomial p(x)=0p(x)=2x 2 −5x−3p(x)=0⇒2x 2 −5x−3=0⇒2x 2 −6x+x−3=0⇒2x(x−3)+1(x−3)=0⇒(2x+1)(x−3)=0x= 2

p(x)=2x 2 −5x−3To find zero of polynomial p(x)=0p(x)=2x 2 −5x−3p(x)=0⇒2x 2 −5x−3=0⇒2x 2 −6x+x−3=0⇒2x(x−3)+1(x−3)=0⇒(2x+1)(x−3)=0x= 2−1

p(x)=2x 2 −5x−3To find zero of polynomial p(x)=0p(x)=2x 2 −5x−3p(x)=0⇒2x 2 −5x−3=0⇒2x 2 −6x+x−3=0⇒2x(x−3)+1(x−3)=0⇒(2x+1)(x−3)=0x= 2−1 ,3

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