Question

The zero of the polynomial p(x) = -9x+9 is *

options:


0

-9

-1

1​

Answer 1

$- 9x + 9 = 0 \\ - 9x = - 9 \\ x = \frac{ - 9}{ - 9} \\ x = 1$

Hence, the answer is last option 1

Answer 2

$\huge\sf\pink{Answer}$

☞ Option D - 1 is the correct answer

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$\huge\sf\blue{Given}$

✭ -9x+9

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$\huge\sf\gray{To \:Find}$

◈ It's zero?

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$\huge\sf\purple{Steps}$

So here let's try substituting the given options in the equation,

➝ -9(0) + 9

➝ 0+9

➝ 9 ≠ 0

Hence 0 is not a zero of the polynomial -9x+9

➳ -9(9)+9

➳ -81+9

➳ -72 ≠ 0

Hence -9 is not a zero of the polynomial -9x+9

»» -9(-1)+9

»» 9+9

»» 18 ≠ 0

Hence -1 is not a zero of the polynomial -9x+9

➠ -9(1)+9

➠ -9+9

➠ 0 = 0

Hence the zero of the polynomial -9x+9 is 1

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