Question

The zero of the polynomialp(x)=x(x-2)(x-3)

Answer 1

Answer:

the answers are 0,2 and 3.

Step-by-step explanation:

Put the polynomial P(x) = 0 as u have to find zeroes.

so x(x-2)(x-3) = 0

equating each factor we get,

x = 0 ------1,

and

x-2 = 0

it implies

=> x = 2 (transporting -2 to R.H.S.) ------2,

and lastly

x-3 = 0

=> x = 3 ---------3

So from equn. 1,2 and 3

we get

x= 0, x= 2 and x= 3.

u can recheck the answers by putting the values of x i.e. 0,2 and 3.

we get P(x) = 0 always.

I hope it helps u...