The zero of the quadratic polynomial 6x^2 + mx +2n is -3/2 and 4/3. Evaluate the value of m and n.
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Sum of roots= -b/a
so, (-3/2 + 4/3)=(-m)/6
(-9+8)/6=(-m)/6
So, m=1
Product of roots=c/a
(-3/2)(4/3)=2n/6
(-2)=n/3
So, n=(-6)
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so, (-3/2 + 4/3)=(-m)/6
(-9+8)/6=(-m)/6
So, m=1
Product of roots=c/a
(-3/2)(4/3)=2n/6
(-2)=n/3
So, n=(-6)
PLZ MARK IT AS BRAINLIEST..
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Answered by
7
Answer:
ANSWER =》 m=1 , n= -6
Step-by-step explanation:
Sum of zeros =-b/a = -(-9+8)/6= -(-1)/6=1/6=1
product of zeros =c/a=(-3/2×4/3)=-6
The required values are m=1 and n=-6
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