Question

the zero's of the polynomial p(x)= x^2 - x - 6​

Answer 1

Answer:

3,-2

Step-by-step explanation:

for P(x) the expression becomes 0

THEN, factorise it into

(x-3)(x+2)=0

this gives either x= 3 or -2 for the equation be true

Answer 2

Answer:

${x}^{2} - x - 6 = \\ {x}^{2} - 3x + 2x - 6 = \\ x(x - 3) + 2(x - 3) = \\ (x + 2)(x - 3) \\ x - 3 = 0 \\ x = 3 \\ x + 2 = 0 \\ x = - 2 \: ok \: ans$

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