the zero (s) of the polynomial x2-8 is:-
(a)8
(b)2√
(c)2√2
(d) √8
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Answer:
b)2√2
Step-by-step explanation:
x^2-8 can also be written as
(x+2√2)(x-2√2). [(a+b)(a-b)= a^2-b^2]
therefore,
x=2√2
x= -2√2
Hope it helps :)
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