Question

the zero's of the quadratic polynomial x^2+25x+156​

Answer 1

Answer:

-12,-13

Step-by-step explanation:

x²+25x+156=0

multiples of 156

1×156

2×78

3×52

4×39

6×26

12×13

hence for splitting two terms

condition

middle term should be splitted in such a way that their sum should be equal to product of coefficient of x² and constant

i.e. 156= 12×13

12+13= 25

hence

x²+12x +13x + 156=0

x( x+12)+ 13(x+12)=0

(x+12)(x+13)=0

x= -12 , -13