Question

The zeroes of 3x^2-4-x

Answer 1

hey mate answer in attachment

Answer 2

$\huge\mathfrak{Solution:}$.

$3 {x}^{2} - x - 4$
$3 {x}^{2} - 4x + 3x - 4$
$x(3x - 4) + 1(3x - 4)$
$(x + 1)(3x - 4)$
$x = -1orx = \frac{4}{3}$
$so \: two \: zeroes \: are \: -1and \: \frac{4}{3}$