Question

The zeroes of a quadratic polynomial p (x) = 3x² + ax + b are
-3/5 and 7/5
Evaluate the values of a and b.​

Answer 1

Answer:

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Answer 2

Answer:

put X=-3/5

3(-3/5)^2+a(-3/5)+b =0

27/25 -3a/5 +b=0

25b-15a=-27 this is equation first

now put x is equal to 7/5

3(7/5)^2 +a(7/5) +b=0

35a+b=-147 this is equation second

by solving equation first and second with elimination method then we will find the values.