Question

The zeroes of a quadratic Polynomial x^2+88x+125 are (what in nature and how)
A question for 20 points...​

Answer 1

Answer:

Just apply the quadratic formula

d= b^2 - 4ac

and then

roots=-b+-√d / 2a

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Answer 2

$\huge\mathbb\green{ANSWER}$

Let A and B be the zeros of given polynomial...

Then,

★ A + B = -88

&

★ A × B = 125

So, This happens when A & B both are negative...

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