Question

The zeroes of mn(x2 + 1) = (m2 + n2)x are​

Answer 1

Answer:

answer is given in attachment

Answer 2

Given,

mn(x²+1) = (m²+n²)x

To find,

The zeroes.

Solution,

The zeroes of mn(x²+1) = (m²+n²)x will be m/n and n/m.

We can easily solve this problem by following the given steps.

According to the question,

mn(x²+1) = (m²+n²)x

Multiplying mn and x into their respective brackets,

mnx²+mn = m²x+n²x

Moving m²x and n²x from the right-hand side to the left-hand side will result in the change of the sign from plus to minus,

mnx²-m²x-n²x+mn = 0

Taking mx common from the first two terms and -n from the last two terms,

mx(nx-m)-n(nx-m) = 0

Taking (nx-m) common,

(nx-m) (mx-n) = 0

Equating both the brackets with zero,

(nx-m) = 0, (mx-n) = 0

nx = m, mx = n

x = m/n, x = n/m

Hence, the zeroes of mn(x²+1) = (m²+n²)x are m/n and n/m.