Question

The zeroes of
of

x2-2x -8
are - -​

Answer 1

Answer:

$x {}^{2} - 2x - 8 = 0 \\ x {}^{2} - 2x - 4x - 8 = 0 \\ x(x - 2) + 4(x - 2) = 0 \\ (x - 2)(x + 4) = 0 \\ x - 2 = 0 \\ x = 2 \\ x + 4 = 0 \\ x = - 4$

Step-by-step explanation:

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Answer 2

Answer:

x²-2x-8

splitting the middle term

= x² - ( 4-2) x - 8

= x² -4x + 2x -8

= x ( x -4 ) + 2 ( x - 4 )

= ( x + 2 ) ( x - 4 )

therefore , x = -2 , 4