the zeroes of p(x)=x3-4x are
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Answered by
5
Step-by-step explanation:
-4 and 1 is the two zeros of polynomial
Answered by
15
Answer:
heya mate there's your answer
To find the zeroes let p(x)=0
x^3-4x=0
x(x^2-4)=0
x=0 and x^2-4=0
x^2=4
x=2
The zeroes of p(x)=x^3-4x are 0,2
hope it helps you.......
Thank you!!!
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