Math, asked by harsh6291, 11 months ago

the zeroes of p(x)=x3-4x are​

Answers

Answered by student8116
5

Step-by-step explanation:

-4 and 1 is the two zeros of polynomial

Answered by manasa1010
15

Answer:

heya mate there's your answer

To find the zeroes let p(x)=0

x^3-4x=0

x(x^2-4)=0

x=0 and x^2-4=0

x^2=4

x=2

The zeroes of p(x)=x^3-4x are 0,2

hope it helps you.......

Thank you!!!

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